dynamic programming - Explain the algorithm to solve 'longest increasing subsequence' problem -

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I have been trying to understand this algorithm for the last 2 hours, but I can not get it. Can anyone explain it easily? 

  function lis_length (a) n: = a.length q: = 0 for n for new array (n): max: = 0; 0 to k for j, if any [k] & gt; A [ja]: if q [j] & gt; Maximum, then Maximum = q [j] Set Q [K]: = Max + 1; For maximum: = 0, I am 0 to n: If q [i] & gt; Maximum, then Maximum = q [i] Set Maximum Return; After the first double (double) loop,  q [i]    
 
 status < />>    
 
 
 
 
  already ends in the status of  j  The largest growing follow-up length, but between  j  and  0  and  k-1 . Given this, how do you calculate  q [k] ?  
 Good, you can type  j  with  j  and  a [j] & lt; One of the [k] , related  q [j]  values ​​is the largest, add one, and hide that value in  q [k]  See for This is what internal loops do.  
 Then in the entry in the internal loop,  q [j]  is already the correct value for  0  and  k-1 Click . And on the exit, there is also the right value for  k , so when a double loop leaves, between  q [i]  in all  i   0  and  n .  
 The final loop makes the largest selection of those people, which is the answer.

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