c - Confused with the char array when scanf -

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मैं एक छोटे से प्रोग्राम से भ्रमित हूं। 

  #include & lt; stdio.h & gt; # परिभाषित LEN 10 int main () {char str1 [LEN] = "\ 0"; चार स्ट्रॉज़ [एलएन] = "\ 0"; Scanf ("% s", str1); Scanf ("% s", str2); Printf ("% s \ n", str1); Printf ("% s \ n", str2); वापसी 0; }   
 अगर मेरा इनपुट है:  
 
 मैंगोबाटाओ 
 मैंगोबैटो 123456   
 आउटपुट क्यों होना चाहिए: < / P> 
 
 123456 
 mangobatao123456   
 और नहीं:  
 
 mangobatao 
 mangobatao123456   
 कैसे  char  सरणी को स्मृति में आवंटित किया गया है?   
 
 < P> ठीक है, एक 10 अक्षर  char  एरे फिट नहीं होगा  "mangobatao" , क्योंकि इसमें 10 अक्षर हैं - शून्य टर्मिनेटर के लिए कोई जगह नहीं है इसका मतलब है कि आपने अपरिभाषित व्यवहार का कारण बना है, इसलिए कुछ भी हो सकता है।  
 इस मामले में, ऐसा लगता है कि आपका कंपाइलर ने  str2  से पहले  str1  स्मृति में, इसलिए जब आप  scanf  को भरने के लिए  str2  पर कॉल करते हैं, तो लंबी स्ट्रिंग  str1  की शुरुआत को ओवरराइट करता है यही कारण है कि आप  str2  को प्रिंट करने का प्रयास करते समय आपको जो कोड की सोच रहे हैं उसका अंत देखें। यदि आप 100 की लंबाई का उपयोग करते हैं तो आपका उदाहरण ठीक काम करेगा।

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