css - a.active what deactivates an active link? -

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कुछ उदाहरण .. 

  #jqt .back.active {-webkit-border- छवि: यूआरएल (आईएमजी / बैक_बटन_क्लाइज्ड पेज) 0 8 0 14; } & Lt; a href = "#" class = "back" & gt; बैक & lt; / a & gt;   
 और  
  #jqt ul li a.active, #jqt ul li a.button {पृष्ठभूमि रंग: # 676c96; रंग: #fff; } & Lt; ul class = "individual" & gt; & Lt; li & gt; & lt; a href = "जावास्क्रिप्ट: कार्ट ('0', 'खाली')" & gt; रद्द करें & lt; / a & gt; & lt; / li & gt; & Lt; li & gt; & lt; a href = "javascript: placeOrder ()" & gt; अब प्लेस ऑर्डर & lt; / a & gt; & lt; / li & gt; & Lt; / ul & gt;   
 जब इनमें से कोई भी सक्रिय स्थिति को धक्का दे रहा है, तो बंद नहीं होता है कोई quirks क्यों या निष्क्रिय करने के लिए मजबूर करने का एक तरीका?  
 thx   
 
 
 थोड़ा भ्रमित प्रश्न।  ए: सक्रिय  लिंक को सक्रिय स्थिति में चुनता है;  a.active  एक वर्ग है, संभवतः जावास्क्रिप्ट द्वारा जोड़ा गया और निकाला जाता है। आपने अपने जेएस को पोस्ट नहीं किया है, इसलिए यह कहना मुश्किल है, लेकिन ऐसा लगता है कि इसमें कोई बग है, और यह तत्वों से ठीक से  सक्रिय  वर्ग को नहीं हटा रहा है, या अपनी स्टाइलशीट में इसका मतलब : सक्रिय ।

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