Scala: Is there a default class if no class is defined? -

According to

, Scala methods belong to a class. However, if I define a method in REPL or in a script that I execute using Scala, then which class is the method?

  Scala> Def Hoho (string: string) = {printlen ("hoho" + ARR)} Hoho: (String: Unit Scale & gt; Hoho ("Rehul") hooh rahul   
 In this example Which class is related to the method?   
 
 
 REPL automatically declares all your statements in the objects (in fact your Wrapping the statement) if you print the intermediate code using the  -Xprint: typer  option, you see it in action Definition:  
  scala> Def hoho (straight: string) = {println ("hoho" + straw)} [[syntax tree at the end of the tipper]] / scala source: & Lt; console & gt; package $ line1 {last object read $ java.lang.object with scalaObject {def this (): object $ line1. $ Read = {$ read.super.this (); ()}; The last object increases java.lang.Object with the $ iw slab object {df (this): object $ line 1. $ Read. $ Iw = {$ iw.super.this (); ()}; The last object $ Increases java.lang.Object with iw slab object {df this (): Object $ line1. $ Read $ Iw $ Iw = {$ iw.super.this (); ()}; Def hoho (str: string): unit = scale.a.prudiff.println ("hoho". (Str))}}}}   
 then your method  should be < / Code> Really  $ line1 Have read $. $ Iw $ Iw.hoho  Then when you use  yes ("foo") , then it will be rewritten to add the package and external object  
 Additional Notes: For scripts,  -Xprint: typer  ( -Xprint: parser ) code is wrapped inside code block  main (arguments: array [ String])  the  main  of an object. You have access to arguments in the form of  args  or  argv .