Passing php variable to jquery -

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  के लिए ($ v = 0; $ v & lt; 11; $ v ++) {echo "& lt; div class = 'सदस्यता रद्द' & gt; & lt; एक वर्ग = 'बटन' & gt; सदस्यता रद्द करें & lt; / a & gt; & lt; / div & gt; "; गूंज "& lt; div id = '$ v' & gt; & lt; / div & gt;"; }   
 मैं चाहता हूं कि कक्षा को रद्द कर दिया जाए ताकि नीचे दिए जाने वाले डिवेल को निकाल सकें। इसलिए इसके लिए मुझे जरूरी $ वी पास करना होगा।  
 यह मैं जेक्यू के साथ शुरू किया है लेकिन मुझे नहीं पता कि कैसे चर $ वी पाने के लिए। मैं इसे कैसे पूरा कर सकता हूं?  
  $। तैयार (फ़ंक्शन () {$ ('सदस्यता रद्द')। निकालें ();});    
 
 
 आपको jquery को कुछ भी देने की आवश्यकता नहीं है:  
  $ (document) .ready (function () {$ ('unsubscribed')। एक ('क्लिक', फ़ंक्शन () {$ (this) .next ()। Remove ();})}} ;   
 यह आपके वर्तमान HTML के लिए काम करता है। 
 अधिक सुरक्षित होने के लिए, आपको उन तत्वों को एक क्लास जोड़ना चाहिए जिन्हें आप हटाना चाहते हैं:  
  ($ V = 0; $ v & lt; 11; $ v ++) {echo "div class = 'unsubscribed' & gt; & lt; एक वर्ग = 'बटन' & gt; सदस्यता रद्द करें & lt; / a & gt; & lt; / div & gt;"; गूंज "& lt; div class = 'to_be_removed' & gt; & lt; / div & gt;"; }   
 इस तरह से आप उस div को संदर्भित कर सकते हैं जिसे आप withouth को हटाना चाहते हैं, यह  सदस्यता रद्द  div:  
  $ (दस्तावेज़) .ready (फ़ंक्शन () {$ ('सदस्यता रद्द की गई')। एक ('क्लिक', फ़ंक्शन () {$ (this) .next ('to_be_removed')। निकालें ();})}} ;

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