python - Extracting elements inside and between brackets -

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I have the following string and what would I like to extract between elements (xx = "yy") and parentheses. Here is an example: [caption id = "get it", align = "and" width = "and" caption = "and this"] also [/ caption]

I've tried the following code but I'm quite a noob with regex. 

  re.sub (r '\ [caption id = "(. *)" Align = "(. *)" Width = "(. *)" Caption = "(. *) "\] (. *) \ [\ / Caption \] ',' token:% 1% 2% 3% 4% 5 ', self-sufficiency, again. NICACAS)   
 In advance Thanks a lot!   
 
 
 This is probably not working for you because . *  Greedy  [^ "] *  try instead in its place.  [^"]  Excerpt is a set of all characters except characters, as well You have stated in the comments, the token syntax is  \\ n , not % n . Try it:  
  re.sub (r '\ [caption id = "([^" * *] "align =" ([^ "] *)" width = "([^ "] *" Caption = "([^"] *) "\] (. *) \ [\ Caption \] ',' token: \\ 1 \\ 2 \\ 3 \\ 4 \\ 5" , Self.content, re.IGNORECASE)   
 Span the content of the caption tag multiple lines? If they do this, then . *  on new lines Instead, you need us something like  [^ \ x00] * .  [^ \ x00]  means the set of all charchators except for a red letter. / P> 
  re.sub (r '\ [caption id = "([^"] *] ([^ \ x00] *) \ [\ / \ "\") caption \]', 'Tow Sans: \\ 1 \\ 2 \\ 3 \\ 4 \\ 5 ", self revolution, re. NICACAS)   
 On the off chance that the actual characters in your strings are legally Can be included, you will need to use the  re.DOTALL  flag instead.

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