permutation - Static sized combinations -

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Hours and I can not come up with a solution.

Let's say I have ABC, I need all its 3 letter combinations, ABC, BBC, CBC etc. Now no ABC etc. Can it be done only with the loop? Any recursion or methods? 

 for  (char ch1 = 'a'; ch1 & lt; = 'c' ; C3 and LT; = 'C'; C3 ++) for (four CH 2 = 'A'; C2 and LT; = 'C'; C2 ++)

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