c++ - referencing problem in void * pointer? -

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यह कोड: 

  int p = 10; शून्य * q; * Q = 10;   
 संकलित नहीं करता है:  
 
 '=': 'int' से 'शून्य *' में कनवर्ट नहीं किया जा सकता   
 हालांकि, यह कोड ठीक संकलित:  
  int p = 10; शून्य * q; Q = & amp; p;   
 इसके पीछे क्या कारण है?   
 
 
 ए <कोड > शून्य *  एक अज्ञात प्रकार के आंकड़ों को इंगित करता है (यदि यह प्रारंभ होता है, जो आपकी नहीं है)।  
 आप केवल एक ज्ञात प्रकार के चर को निर्दिष्ट कर सकते हैं या ज्ञात प्रकार।  
  int p = 10; शून्य * q = & amp; p; * (इंट *) क्यू = 20; अगर (पी! = 20) ... कुछ बहुत ही गलत हो गया है ...   
 यह  शून्य *  को एक  को बदलता है * int *  और उसके बाद एक dereferenced पूर्णांक पॉइंटर के लिए एक मान निर्दिष्ट करता है।

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