Why isn't my perl one liner working? -

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I'm trying to get the number of errors from an HTML log file. Here is my code (yes, I know that I'm mixing bash and pearl): 

  for line in path path- txt`; Grep failed $ {line} | Perl -pe 'm / \ d + /';   
 I just hope to get a list of numbers, for example,  
  0 0 0 0 6  < / Pre  
 
  Total failure: & lt; Strong> 0 & lt; / Strong> But instead I am getting the full line which has an error, e.g. Total failure: & lt; Strong & gt; 1 & lt; / Strong> Total failure: & lt; Strong & gt; 0 & lt; / Strong> Total failure: & lt; Strong & gt; 0 & lt; / Strong> Total failure: & lt; Strong & gt; 0 & lt; / Strong> Total failure: & lt; Strong & gt; 1 & lt; / Strong> Total failure: & lt; Strong & gt; 6 & lt; / Strong>    
 What am I seeing?   
 
 
  perl -pe 'm / \ d + /';  Just display a pattern match, the printed line will not be changed. If you only want to print the number, then you need something:  
  perl -pe 's / \ D + // g' # change $ _   
 or  
  perl -nE 'says $ 1 if / (\ d +) /' # print match only   
 but Why not use all the Pearl?  
  perl -nwE '$ 1 if say /Failed.*(\d+)/'passs.txt

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